executing php in a wordpress blog post?

[spacedog]

I'd like to execute php in a wordpress blog post but can't get it to work.

I tried two different plugins, neither of them work.

exec php & run php.

With exec php after entering code between the tags it just shows the code in the post instead of showing what the code is telling it to show.

Anyone know a way to solve this?

[LD]

Same problem here. I can give you a couple of others to try...didn't work for me, but maybe you'll have better luck.

http://www.daikos.net/widgets/daikos-text-widget/

http://www.erik-rasmussen.com/blog/2...tize-anything/

I'm trying to drop in some php from Dragonscrips, and it just says "cannot connect to server"

If you figure it out, let me know...

[walrus]

I run exec.php and am able to add php to pages without any problem. have never tried posts but can't imagine it would be different.

[Useless]

Originally Posted by walrus

I run exec.php and am able to add php to pages without any problem. have never tried posts but can't imagine it would be different.

That's what I've used and works fine within posts. I believe it's another situation in which you want to turn off the Visual Rich Editor.
http://bluesome.net/post/2005/08/18/50/

[walrus]

Originally Posted by Useless Warrior

That's what I've used and works fine within posts. I believe it's another situation in which you want to turn off the Visual Rich Editor.
http://bluesome.net/post/2005/08/18/50/

Or, in other words, read the fucking manual

[spacedog]

Originally Posted by walrus

Or, in other words, read the fucking manual

yep. did everything it said.. even installed the role manager, etc..

tried several times & nothing works.. not in a post nor as a page.

I have tgp on root & blog in dir.

Script is in root & trying to include tgp script in post thats on blog in dir as

<?
 include("../script.php");
 $query   = "SELECT COUNT(url) AS numrows FROM links";
 $result  = mysql_query($query) or die('Error, query failed');
 $row     = mysql_fetch_array($result, MYSQL_ASSOC);
 $numrows = $row['numrows'];
 
 $maxPage = ceil($numrows/65);

 $sql = "SELECT url, title, date FROM `links` ORDER BY date DESC LIMIT ".$offset.", 65;";
 $rs = mysql_query($sql);
 echo mysql_error();
 
 
 $self = $_SERVER['PHP_SELF'];
 $nav = '';
 for($page = 1; $page <= $maxPage; $page++)
 {
    if ($page == $pageNum)
    {
        $nav .= " $page ";
    }
    else
    {
        $nav .= " <a href=\"$self?page=$page\">$page</a> ";
    }
 }

while($row = mysql_fetch_row($rs)){
     echo "<a href=\"".$row[0]."\">".$row[1]."</a>".$row[2]."\n<br>\n";}

 echo "<p>Page: ";
 $self = $_SERVER['PHP_SELF'];
 $nav = '';
 for($page = 1; $page <= $maxPage; $page++)
 {
    if ($page == $pageNum)
    {
        $nav .= " $page ";
    }
    else
    {
        $nav .= " <a href=\"$self?page=$page\">$page</a> ";
    }
 }

echo $first . $prev . $nav . $next . $last;
 mysql_close();
?>

and I end up with on the post

You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near ‘ 65′ at line 1
Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /dirname/0/blahblah/htdocs/file/name/wp-content/plugins/exec-php/runtime.php(41) : eval()’d code on line 29