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#1 |
a.k.a. Sparky
Join Date: Sep 2004
Location: West Palm Beach, FL, USA
Posts: 2,396
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hehe, ok, ethernet 101
Ethernet is a collision avoidance network scheme. The way it works, machine A sends traffic to Machine B, Machine C, D, E, F, G all hear those broadcasts, but, ignore the traffic because it isn't destined for them. If Machine A and Machine C send traffic at the same time, each will wait a random amount of time and retransmit -- until the packet goes through. This is a half-duplex circuit. Half-duplex = bad. ![]() So, the engineers said, lets develop a switch, but, to avoid collisions (collisons beget retries, retries = latency, latency = worse performance) we'll design a system that only sends traffic to the machine or wire that it is destined for. There are two major designs for switches, cut-through and store and forward. I think 99% of the switches today are store and forward. With either, a machine could run full duplex without having to worry about collisions between the machine and the switch. With a cut-through switch, the switch itself would detect the collision and signal the retry, but, it was like a virtual relay that would jumper the wire so that traffic would flow directly. Store and forward would buffer the request and send it so that the collision would be avoided. Of course, if you have 1 internet connection and 23 machines hooked to a switch, that first port has a lot of contention, and probably does have collisions, but, overall, the rest of the network runs faster because they are not listening to traffic unless it is destined for them. But, you need more than 23 machines, so, you buy another switch and connect it to port 2. Now you have to figure out where to send the traffic, so, each mac address does a little broadcast, and the proxy arp tells the first switch, hey, I have these 8 mac addresses and the first switch says, ok, anything destined for those 8 gets sent down port 2's wire for the other switch to handle. Well, pretty soon, a large enough network will have more than 1024 mac addresses to contend with. The 'core' switch must then figure out where to send that traffic, but, if it exceeds the number of entries allowed in the spanning tree, it will spend quite a bit of time discovering where those machines are. That's sort of the basic theory behind it.
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#2 |
HEY NOW!
Join Date: Apr 2004
Location: in the Matrix Glitching on an Endless Loop. Loop. Loop. Loop. Loo
Posts: 1,218
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Sparky why don't you just unveil your time machine and become a billionare already
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don't mind me im nothing but nonsense <3 |
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#3 | |
a.k.a. Sparky
Join Date: Sep 2004
Location: West Palm Beach, FL, USA
Posts: 2,396
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Quote:
For fun, I write code and run a hosting company. ![]() oh cool. sig placement. haha
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#4 | |
You tried your best and you failed miserably. The lesson is 'never try'
Join Date: Oct 2004
Posts: 166
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Quote:
The switch sends configuration BPDUs to communicate and compute the spanning-tree topology. A MAC frame conveying a BPDU sends the switch group address to the destination address field. All switches connected to the LAN on which the frame is transmitted receive the BPDU. BPDUs are not directly forwarded by the switch, but the information contained in the frame can be used to calculate a BPDU by the receiving switch, and, if the topology changes, instigate a BPDU transmission. The answer to your question Cleo is no, there might not be a warning of a problem because the switch is doing exactly what its suppose to do, recalculate the tree. However, it is possible for forge BPDU and cause the main, or *root* switch to constantly update the tree resulting in a form of DoS attack. My servers stopped sending traffic about 4 this morning, I doubt corey was making changes to the network at that time of the morning. Considering that and the way Danny's post was worded, I'll bet it was the upstream provider having trouble. |
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